Question

The number of tickets Brianna can buy for a sports fundraiser varies inversely to the price of each ticket. Brianna could buy 25 tickets at $5 each.

Write the equation that relates the number of tickets, N, that Brianna can buy to the price, p, of each ticket.

How many tickets could Brianna buy if the price of each ticket was $2.50?

Answer 1

Answer:

Part 1) $p=125/N$

Part 2) $50\ tickets$

Step-by-step explanation:

Part 1) Write the equation

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem

Let

p ----> the price of each ticket

N ---> the number of tickets

so

$pN=k$

we have

For N=25, p=$5

Find the value of k

$k=pN$

substitute the given values

$k=5(25)=125$

so

The equation is equal to

$p=125/N$

Part 2) How many tickets could Brianna buy if the price of each ticket was $2.50?

For p=$2.50

substitute the value of p in the equation and solve for N

$2.50=125/N$

$N=125/2.50=50$

Answer 2

Answer:

N=125/P, Brianna could buy 50 tickets

Step-by-step explanation:

We are given that N, the number of tickets Brianna can buy, varies inversely with the price, p, of each ticket. So N=k/p for some constant, k. To determine the value of k, substitute the known values, N=25 when p=5, to find that

25=k/5

Multiplying by 5 gives k=125, so an equation that relates N and p is

N=125/p

Substituting p=2.50 gives

125/2.50=50

So Brianna could buy 50 tickets if the price of each ticket was $2.50.