Respuesta :
Plot the graphs of the given equations.
Part a)
Given the equation
[tex]y\:=\:x-2[/tex]
Determining x-intercept:
[tex]\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0[/tex]
[tex]x-2=0[/tex]
[tex]\mathrm{Add\:}2\mathrm{\:to\:both\:sides}[/tex]
[tex]x-2+2=0+2[/tex]
[tex]x=2[/tex]
So x-intercept is (2, 0)
Determining x-intercept:
[tex]y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0[/tex]
[tex]y=0-2[/tex]
[tex]\mathrm{Subtract\:the\:numbers:}\:0-2=-2[/tex]
[tex]y=-2[/tex]
So y-intercept is (0, -2)
Also
[tex]\mathrm{Slope\:of\:}x-2:\quad m=1[/tex]
The graph of the equation is attached below, where red line indicates the graph of the equation [tex]y\:=\:x-2[/tex].
Part b)
Given the equation
[tex]y\:=\:2x\:-\:8[/tex]
Determining x-intercept:
[tex]\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0[/tex]
[tex]2x-8=0[/tex]
[tex]\mathrm{Add\:}8\mathrm{\:to\:both\:sides}[/tex]
[tex]2x-8+8=0+8[/tex]
[tex]2x=8[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}2[/tex]
[tex]\frac{2x}{2}=\frac{8}{2}[/tex]
[tex]x=4[/tex]
So x-intercept is (4, 0)
Determining x-intercept:
[tex]y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0[/tex]
[tex]y=2\cdot \:0-8[/tex]
[tex]\mathrm{Apply\:rule}\:0\cdot \:a=0[/tex]
[tex]y=0-8[/tex]
[tex]\mathrm{Subtract\:the\:numbers:}\:0-8=-8[/tex]
[tex]y=-8[/tex]
So y-intercept is (0, -8)
Also
[tex]\mathrm{Slope\:of\:}2x-8:\quad m=2[/tex]
The graph of the equation is attached below, where blue line indicates the graph of the equation [tex]y\:=\:2x\:-\:8[/tex].

