Answer:
[tex](3x + 1)(3x + 11)[/tex]
Step-by-step explanation:
We want to factorize:
[tex]9 {x}^{2} + 36x + 11[/tex]
Where a=9, b=36, and c=11
ac=9×11=99
To factors of 99 that sums to 36 are 3,33
We split the middle term to get:
[tex]9 {x}^{2} + 33x + 3x + 11[/tex]
We factor by grouping
[tex]3x(3x + 11) + 1(3x + 11)[/tex]
The factorization is
[tex](3x + 1)(3x + 11)[/tex]
