Answer:
[tex]a= \frac{- 12 (C + A)}{C + A - 1} [/tex]
Step-by-step explanation:
Assuming we want to solve:
[tex]C=\frac{a}{a+12}-A[/tex]
Add A to both sides;
[tex]C + A=\frac{a}{a+12}[/tex]
Cross multiply;
[tex](C + A)(a + 12) = a[/tex]
Expand:
[tex]a(C + A) + 12 (C + A) = a[/tex]
Group similar terms:
[tex]a(C + A) - a= - 12 (C + A)[/tex]
Factor:
[tex]a((C + A) - 1)= - 12 (C + A)[/tex]
[tex]a= \frac{- 12 (C + A)}{C + A - 1} [/tex]
