Question

Please help
Trig: Laws of Cosines.
In Δ ABC , side a =3, side b =15 and m < C= 108* . Find side ' c' to the nearest integer.

Answer 1

Answer: 16

Step-by-step explanation:

law of cosines says that c^2 = a^2 + b^2 -2abcosC

so c^2 = 3^2 +15^2 - 2*2*15*cos108

c^2 = 234 -  (-27.8115294937 )

c^2 = 261.811529494

c = 16.18 rounds to 16

Answer 2

Answer:

16

Step-by-step explanation:

c² = a² + b² - 2(a)(b)cos(C)

c² = 3² + 15² - 2(3)(15)cos(108)

c² = 261.8115295

c = 16.18059114