Answer:
[tex](x+2)^2-2[/tex]
Step-by-step explanation:
we have the expression
[tex]x^2+4x+2[/tex]
Convert to vertex form
[tex]a(x-h)^2+k[/tex]
where
a is the leading coefficient
(h,k) is the vertex
Complete the square
[tex](x^2+4x+2^2)+2-2^2[/tex]
[tex](x^2+4x+2^2)-2[/tex]
Rewrite as perfect squares
[tex](x+2)^2-2[/tex]
so
The coefficient a =1
The vertex is the point (-2,-2)