Respuesta :

Answer:

[tex](x+2)^2-2[/tex]

Step-by-step explanation:

we have the expression

[tex]x^2+4x+2[/tex]

Convert to vertex form

[tex]a(x-h)^2+k[/tex]

where

a is the leading coefficient

(h,k) is the vertex

Complete the square

[tex](x^2+4x+2^2)+2-2^2[/tex]

[tex](x^2+4x+2^2)-2[/tex]

Rewrite as perfect squares

[tex](x+2)^2-2[/tex]

so

The coefficient a =1

The vertex is the point (-2,-2)

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