Question

The math club sells candy bars and drinks during football games.
​ ∙ 60 candy bars and 110 drinks will sell for $265 . ​​
​ ∙ 120 candy bars and 90 drinks will sell for $270.
​How much does each candy bar sell for?
​(Note: Express the answer in dollars.cents.)​

Answer 1

Answer:

The price of candy bar is 75 cents

Step-by-step explanation:

Let c be the price of candy bar and d be the price of drinks

Then according to given statements

$60c+110d = 265\ \ \ \ Eqn\ 1\\120c+90d = 270\ \ \ \ Eqn\ 2$

Multiplying equation 1 by 2

$120c+220d = 530\ \ \ \ Eqn\ 3$

Subtracting equation 2 from equation 3

$120c+220d - (120c+90d) = 530 - 270\\120c+220d-120-90d = 260\\130d=260$

Dividing both sides by 130

$\frac{130d}{130} = \frac{260}{130}\\d = 2$

Putting d=2 in equation 1

$60c+110(2) = 265\\60c + 220 = 265\\60c+220-220 = 265-220\\60c=45\\c = \frac{45}{60}\\c = 0.75$

Price of candy bar is $0.75 or 75 cents

Hence,

The price of candy bar is 75 cents