Answer:
Ksp = 1.64 ×10⁻⁵
Explanation:
Given data:
Mass of Ag₂SO₄ = 5.0 g
Volume of water = 1.0 L
Solubility product = Ksp = ?
Solution:
First of all we will calculate the molarity.
Molarity = Number of moles of solute / Volume of solution in L
Number of moles = mass/ molar mass
Number of moles = 5.0 g/311.74 g/mol
Number of moles = 0.016 mol
Molarity = 0.016 mol / 1 L
Molarity = 0.016 M
Dissociation equation:
Ag₂SO₄ ⇔ 2Ag⁺ + SO₄²⁻
Ksp = [Ag⁺]² [SO₄²⁻]
Ksp = [0.032]²[0.016]
Ksp = 1.64 ×10⁻⁵
