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r3t40

The quadratic function has a general form of,

[tex]f(x)=ax^2+bx+c[/tex]

Where [tex]a,b,c[/tex] are coefficients.

In your case the quadratic function is given in its general form,

[tex]f(x)=x^2-5x+6[/tex]

The corresponding coefficients are thus [tex]a=1,b=-5,c=6[/tex].

The only constant term is c which is also a coefficient.

Hope this helps.

Answer:

Coefficient is-5

Constant is 6

Step-by-step explanation:

According to the quadratic formula

ax^2+bx+c

So b is the coefficient and c is the constant

So let's go back to the question

X2-5x+6

So the coefficient is -5

And the constant is 6

But since we can actually solve the question further so let's solve

X2-5x+6

Let's factorise

X2-3x-2x+6

X(x-3)-2(x-3)

(X-2)(x-3)

X-2=0

X=2

X-3=0

X=3

Therefore x is 2 or x is 3

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