stated method in question is wrong!
Step-by-step explanation:
We need to find the general solution of x ! for the equation [tex]tan x + tan 2x = 0[/tex]
⇒ [tex]tan x + tan 2x = 0[/tex]
⇒ [tex](tan x + tan 2x)-tan2x = 0-tan2x[/tex]
⇒ [tex]tan x = -tan2x[/tex]
Now , we know that [tex]tan(\pi -2x) = -tan2x[/tex]
⇒ [tex]tan x = -tan2x[/tex]
⇒ [tex]tan x = tan(\pi -2x)[/tex]
Now , we know that [tex]TanA = TanB \\A=B[/tex]
⇒ [tex]tan x = tan(\pi -2x)[/tex]
⇒ [tex]x = \pi -2x[/tex]
⇒ [tex]3x = \pi[/tex]
⇒ [tex]x = \frac{\pi}{3}[/tex] ......(1)
General solution of Tan x is : [tex]x = n\pi + \alpha[/tex] , \
Here , from equation (1) we get [tex]\alpha =\frac{\pi }{3}[/tex] . Hence general solution is :
⇒ [tex]x = n\pi +\frac{\pi }{3}[/tex] .Therefore , stated method in question is wrong!