Respuesta :

Hi1315

Answer:

[tex]x = - 1 \\ y = {x}^{2} - 5x + 3 \\ y = - 1 - 5 \times - 1 + 3 \\ y = - 1 + 5 + 3 \\ y = 7[/tex]

[tex]x = 2 \\ y = {x}^{2} - 5x + 3 \\ y = 4 - 5 \times 2 + 3 \\ y = 4 - 10 + 3 \\ y = - 6 + 3 \\ y = - 3[/tex]

[tex]x = 4 \\ y = {x}^{2} - 5x + 3 \\ y = 16 - 5 \times 4 + 3 \\ y = 16 - 20 + 3 \\ y = - 4 + 3 \\ y = - 1[/tex]

The confusion here is the multiplication and addition, let me clear

In the -1 value of the table

X²= -1×-1 (first = - x -=+ and 1×1 is 1 so the answer is 1) you apply this to every other multiplication

For the addition let me add the 4 value of the table

We have 16+(-20)+3

First you multiply the signs +×-=-

Then you have

16-20+3

-4+3

-1 this is the answer

Tip

-×-=+

+×+=+

-×+=-

+×-=-

Then when you have a bigger number being subtracted from a smaller number, for example

16-20

You subtract the small number from big number

20-16

4

Then add a minus sign

-4

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