Question

solve the following simultaneouse equation. 3x+y=1 and x²+y²=5​

Answer 1

Answer:

x=2/5,      y=11/5

or x=−1y = 2

Step-by-step explanation:

Substitute y=3x+1 in x2+y2=5 to obtain

x2+(3x+1)2=5    ⇒    10x2+6x−4=0

Hence

5x2+3x−2=0    ⇒    5x2+5x−2x−2=0    ⇒5x(x+1)−2(x+1)= 0   ⇒ (5x−2)(x+1)=0

Hence

either

x=2/5, y=3×2/5+1=11/5

or x=−1, y=3×(−1) +1 = −2