Question

Q27) A racing car can be slowed with a deceleration of -11 m/s?. If it is moving with 55 m/s how for
will it travel to stop, express your answer in scientific notation?
a) 2.4 x10 m
b) 4.1 x10 m
C) 1.4
102 m
d) 3.2 10m

Answer 1

Answer:

C

Explanation:

We know, v^2 = u^2 + 2as

Putting in the values, we get,

0^2 = 55^2 + ( 2 * (-11) * s )

22s = 3025

s = 137.5 = 1.375 * 10^2 ≈ 1.4 * 10^2