Question

The difference of two negative integers is 8 and their product is 48.Find the two integers.

Answer 1

Answer:

The answer is 12 and 4

Step-by-step explanation:

1st equation: -x-(-y)=8

2nd equation: (-x)(-y)=48

-x-(y)=8

-x+y+8

y=x+8

-x(x+8)=48

-x^2-8x=48

Multiply -1

x^2+8x=-48

x^2+8x+48=0

(x+12)(x-4)=0

x=-12

x=4

Check:

-(-12)-(4)=8

12-8=8

8=8

(-12)(-4)=48

48=48