Question

1 What is the pressure on a surface when a force of 50N
acts on an area of
0 20m2,
ON) 0.50m2?
Apressure of 10 Pa acts on an area of 3.0 m2. What is
the force acting on the area?​

Answer 1

The pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².

The force acting on area of 3 m² with pressure 10 Pa is 30 N.

Explanation:

Pressure acting on any surface is the amount of force experienced by that surface in a given area. So it is the ratio of force to area of the object under consideration.

As here the force is said to be 50 N and the area is said to be 20 m², the pressure will be

$Pressure = \frac{Force}{Area} = \frac{50}{20}=2.5 Nm^{2}$

So, pressure is inversely proportional to the area and directly proportional to the force acting on the surface. As it can be seen that on decreasing the area to 0.5 m², there will be increase in the pressure as shown below,

$Pressure = \frac{50}{0.5} = 100 Nm^{2}$

Thus, the pressure increased to 100 Nm² from 2.5 Nm² on decreasing the area from 20 m² to 0.5 m².

Similarly, if 10 Pa pressure is acting on an area of 3 m², then the force acting on this region will be the product of pressure with the area.

$Force = Pressure * Area = 10 * 3 = 30 N.$

Thus, the pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².

The force acting on area of 3 m² with pressure 10 Pa is 30 N.