Use a separate sheet of paper to solve the system of inequalities by graphing. Use the graph to decide if the point (1, –1) is in the solution set of the system. Explain your answer in the box provided below. y≤-3x+3 3x+8y≥3

With inequalities you have to know a few things. First, when you graph you may have to use non solid lines. for instance, if you had x<5, 5 would not be part of the answer because it is only answers less than 5. so you represent this by making a dashed line that says "you cannot include values on this line". Second, with algebra, if you multiply both sides by a negative it flips the inequality. for instance -y > 54 you would multiply (or divide) by -1 and it would change to y < -54. Third, when graphing an inequality, treat it like an equation and graph the line as if it were said equation(with solid or dashed lines as needed) then, if it is y > f(x) you shade in the section above the line and y < f(x) shades in below. The shaded part is your answer basically. Now lets get into yours.

y≤-3x+3

It is already in the form y = f(x) so grapht he line 3x + 3 with a solid line since it is y is less than or equal to, then shade below that line.

3x+8y≥3

First get it so y is by itself

3x+8y≥3

8y≥3 - 3x

y ≥ 3/8 - 3/8 x

Now grapht his line with a solid line and shade the area above it.

Now, the shaded area below between y ≥ 3/8 - 3/8 x and y≤-3x+3 and the lines are your answer, so you need to check if the point (1, -1) is in this shared shaded area or on one of the lines.

The answer is no though, the point (1,-1) is below both.