Question

1. Complete the following:

a. How many moles of C6H12O6are in 13.6 grams C6H12O6?

b. How many grams are required if 2.08 moles of CaCl2is needed for a reaction?

Answer 1

Answer: Part A answer is 180.15588. Part B answer is the moles of HCL required to react with 10 grams of calcium hydroxide.

Explanation:

I just calculated my equation and got my answer.

Answer 2

Answer:

a. 0.076mole

b. 230.88g

Explanation:

a. We'll begin by calculating the molar mass of C6H12O6. This is illustrated below:

Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 13.6g

Number of mole of C6H12O6 =?

Number of mole = Mass /Molar Mass

Number of mole of C6H12O6 = 13.6/180

Number of mole of C6H12O6 = 0.076mole.

Therefore, 0.076mole of C6H12O6 is present in 13.6g of C6H12O6.

b. Let us calculate the molar mass of CaCl2. This is illustrated below:

Molar Mass of CaCl2 = 40 + (35.5x2) = 40 + 71 = 111g/mol

Number of mole of CaCl2 = 2.08 moles.

Mass of CaCl2 =?

Mass = number of mole x molar Mass

Mass of CaCl2 = 2.08 x 111

Mass of CaCl2 = 230.88g

Therefore, 230.88g is required.