Answer:
680.6 N
Explanation:
The net force here is the resultant force. Taking that the two given forces act perpendicular to each other then the resultant is the hypotenuse. Therefore, [tex]R=\sqrt {d^{2}+s^{2}}[/tex] where d is the magnitude of downward force and s is the magnitude of the sideways force. Substituting 631 N for downward force and 255 N for sideways force then [tex]R=\sqrt {631^{2}+255^{2}}=680.5776958\approx 680.6 N[/tex]
Therefore, the magnitude of net force is equivalent to 680. 6 N