Answer:
Given
Time (T) = 0.002 sec
Velocity(V) = 344 m/s
Frequency (f) = ?
Wavelength (w) = ?
Explanation:
We know that
Frequency (f) = 1/ t
= 1/ 0.002
= 500 hertz
Now
wavelength = V/f
= 344/500
= 0.688 m
The frequency and wavelength of the sound wave with the given time period and speed are 500Hz and 0.688m respectively.
Period is simply the time taken for a complete cycle of vibration to pass a given point. Frequency is expressed as;
f = 1/T
Where f is frequency and T is period of time.
Given that;
f = 1/0.002s
f = 500s⁻¹
f = 500Hz
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
From the wavelength, frequency and speed relation,
λ = s ÷ f
Where λ is wavelength, s is speed and f is frequency.
Given that;
λ = s ÷ f
λ = 344m/s ÷ 500s⁻¹
λ = 0.688m
Therefore, the frequency and wavelength of the sound wave with the given time period and speed are 500Hz and 0.688m respectively.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701
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