Answer:
1M
Explanation:
Given parameters:
Volume of Ca(OH)₂ = 25mL = 0.025dm³
Concentration = 1.1M
Volume of HNO₃ = 55mL = 0.055dm³
Unknown:
Concentration of HNO₃ = ?
Solution:
To solve this problem, we must bear in mind that this an acid-base titration. In this reaction, an acid is used to neutralize a base.
The reaction equation is shown below;
Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O
Start from the given and known reactant first. Here it is Ca(OH)₂ ;
Find the number of moles of Ca(OH)₂ first.
Number of moles Ca(OH)₂ = concentration x volume
= 1.1 x 25 x 10⁻³
= 0.028moles
From the reaction equation;
1 mole of Ca(OH)₂ reacted with 2 moles of HNO₃
0.028 moles of Ca(OH)₂ will react with 2 x 0.028
= 0.055moles of HNO₃
Now that we know the number of moles, we can find the concentration of HNO₃;
Concentration of HNO₃ = [tex]\frac{number of moles }{volume}[/tex]
= [tex]\frac{0.055}{0.055}[/tex]
= 1M
