Answer:
Therefore,
[tex]AB=\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right][/tex]
Step-by-step explanation:
Given:
Matrix A and B
[tex]A =\left[\begin{array}{cc}1&2\\2&5\\\end{array}\right] \\\\\\B =\left[\begin{array}{cc}5&-2\\-2&1\\\end{array}\right][/tex]
To Find:
AB = ?
Solution:
First step to check multiplication is exist or not
If number of columns of A matrix is equal to number of rows of B matrix
then Multiplication of AB exist
Here it is equal that is 2
So,
[tex]AB=\left[\begin{array}{cc}1&2\\2&5\\\end{array}\right]\left[\begin{array}{cc}5&-2\\-2&1\\\end{array}\right] \\\\\\AB=\left[\begin{array}{cc}1\times 5+2\times -2&1\times -2+2\times 1\\2\times 5+5\times -2&2\times -2+5\times 1\\\end{array}\right]\\\\\\AB=\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right][/tex]
Which is an Identity Matrix
Therefore,
[tex]AB=\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right][/tex]