Respuesta :
60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.
Explanation:
Data given:
V1 = 75 ml
T1 = 30 Degrees or 273.15 + 30 = 303.15 K
P1 = 91 KPa
V2 =?
P2 = 1 atm or 101.3 KPa
T2 = 273.15 K
At STP the pressure is 1 atm and the temperature is 273.15 K
applying Gas Law:
[tex]\frac{P1VI}{T1}[/tex]= [tex]\frac{P2V2}{T2}[/tex]
putting the values in the equation of Gas Law:
V2 = [tex]\frac{P1V1T2}{P2T1}[/tex]
V2 = [tex]\frac{91 X 75 X 273.15}{303.15 X 101.3}[/tex]
V2 = 60.7 ml
at STP the volume of carbon dioxide gas is 60.7 ml.
The volume of a sample of CO2 at STP should be 60.7 ml.
Gas law:
Since
V1 = 75 ml
T1 = 30 Degrees or 273.15 + 30 = 303.15 K
P1 = 91 KPa
P2 = 1 atm or 101.3 KPa
T2 = 273.15 K
At STP the pressure should be 1 atm and the temperature is 273.15 K.
Here we applied gas law
p1v1/t1 = p2v2/t2
v2= p1v1t2/p2t1
= 9.1*75*273.15/303.15*101.3
= 60.7 ml
Hence, The volume of a sample of CO2 at STP should be 60.7 ml.
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