Question

find the valuesof integers x and y: x^(8)+16y^(8)=0

Answer 1

Answer:

x=0,

y=0

Step-by-step explanation:

$x^8+16y^8=0\\(x^{2}) ^{4} +16(y^{2}) ^{4} =0\\x^2\geq 0,y^2\geq 0\\sum~ of ~two ~positive~ integers ~is~ zero~ if~ each=0\\so~x=0,~y=0$