A train leaves a station and travels north at a speed of 75 mph. Two hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet?

Respuesta :

Answer:

At a distance of 525 km from the station both trains meet.

Step-by-step explanation:

Speed of the first train [tex]S_{1}[/tex] = 75 [tex]\frac{m}{hr}[/tex]

Speed of the second train [tex]S_{2}[/tex] = 105 [tex]\frac{m}{hr}[/tex]

Distance traveled by first train in two hours = 75 × 2 = 150 km

When the first train traveled a distance of 150 km than second train starts from the station.

Let suppose the two trains meet after T hours.

Value of T is given by

[tex]T = \frac{D}{S_{1} - S_{2} }[/tex]

Put the value of D & [tex]S_{1}[/tex] & [tex]S_{2}[/tex] we get

[tex]T = \frac{150}{105 - 75}[/tex]

T = 5 hours

Thus the two trains meet after 5 hours &

⇒ Distance from the station is = Speed of second train × 5

⇒ Distance from the station is = 105 × 5

⇒ Distance from the station is = 525 km

Therefore at a distance of 525 km from the station both trains meet.

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