Respuesta :

the  rational expression [tex]\frac{x^2 - 10x +21}{ x^2-6x -7}[/tex]  to its lowest term is [tex]\frac{x-3}{ x+1}[/tex] .

Step-by-step explanation:

Here we need to reduce the  rational expression x^2 - 10x + 21/ x^2 -6x -7 to its lowest term . Let's find out:

[tex]\frac{x^2 - 10x +21}{ x^2-6x -7}[/tex]

⇒ [tex]\frac{x^2 - 7x-3x +21}{ x^2-7x+x -7}[/tex]

⇒ [tex]\frac{x(x - 7)-3x +7(3)}{ x(x^-7)+x -7}[/tex]

⇒ [tex]\frac{x(x - 7)-3(x -7)}{ x(x^-7)+1(x -7)}[/tex]

⇒ [tex]\frac{(x-3)(x - 7)}{ (x+1)(x^-7)}[/tex]

⇒ [tex]\frac{(x-3}{ (x+1)}[/tex]

⇒ [tex]\frac{x-3}{ x+1}[/tex]

Therefore , the  rational expression [tex]\frac{x^2 - 10x +21}{ x^2-6x -7}[/tex]  to its lowest term is [tex]\frac{x-3}{ x+1}[/tex] .

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