Given the median QR and trapezoid mnpo, what is the value of x?
MN = 17
QR = X+12
OP = 5X-14

The answer for the image is written below.
Given:
Measure of ∠T = (4x + 12)°
Measure of ∠P = 2x°
To find:
The value of x.
Solution:
By the property of isosceles trapezoid:
Adjacent angles corresponding to parallel sides are supplementary.
m∠T + m∠P = 180°
(4x + 12)° + 2x° = 180°
4x° + 12° + 2x° = 180°
Add like terms.
6x° + 12° = 180°
Subtract 12° from both sides.
6x° + 12° - 12° = 180° - 12°
6x° = 168°
Divide by 6 on both sides, we get
x° = 28°
x = 28
The value of x is 28.