Answer:
see the explanation
Step-by-step explanation:
step 1
Find the volume of the water
we know that
The volume of water on the roof can be found by multiplying the length of the roof by the width of the roof by the depth of the water.
so
[tex]V=LWH[/tex]
where
L is the length
W is the width
H is the deep of the water
Remember that
[tex]1\ ft=12\ in[/tex]
we have
[tex]L=22\ ft\\W=12\ ft\\H=8\ in=8/12=2/3\ ft[/tex]
substitute
[tex]V=(22)(12)(2/3)=176\ ft^3[/tex]
step 2
Find the weight of the water
we know that
The density of water is equal to
[tex]62.4\ \frac{lb}{ft^3}[/tex]
Multiply the density by the volume to obtain the weight of the water
[tex]62.4(176)=10,982.4\ lb[/tex]
Convert to kilograms
Remember that
[tex]1\ lb=0.45\ kg[/tex]
so
[tex]10,982.4\ lb=10,982.4(0.45)=4,942.08\ kg[/tex]
That's 4.9 tons of water pushing down on that roof
