Answer:
Each leg is 8 units long
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
Any right triangle must satisfy the Pythagorean Theorem
so
[tex]c^2=a^2+b^2[/tex]
where
c is the hypotenuse (greater side)
a and b are the legs (perpendicular sides)
In this problem we have
[tex]a=AC\\b=BC\\AC=BC\\c=AB=8\sqrt{2}\ units[/tex]
substitute
[tex](8\sqrt{2})^2=a^2+b^2[/tex]
[tex](8\sqrt{2})^2=2a^2[/tex]
[tex]128=2a^2[/tex]
[tex]a^2=64\\a=8\ units[/tex]
therefore
[tex]AC=BC=8\ units[/tex]
Each leg is 8 units long