Respuesta :

Answer:

[tex]x=\frac{1\pm\sqrt{(-1)^{2}+4(7)(9)}} {2(7)}[/tex]

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

[tex]ax^{2} +bx+c=0[/tex]

is equal to

[tex]x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]7x^{2} -x-9=0[/tex]  

so

[tex]a=7\\b=-1\\c=-9[/tex]

substitute in the formula

[tex]x=\frac{-(-1)\pm\sqrt{-1^{2}-4(7)(-9)}} {2(7)}[/tex]

[tex]x=\frac{1\pm\sqrt{(-1)^{2}+4(7)(9)}} {2(7)}[/tex]

[tex]x=\frac{1\pm\sqrt{253}} {14}[/tex]

Answer:

The answer is the D :)

ACCESS MORE
EDU ACCESS
Universidad de Mexico