Respuesta :
Answer:
Circumference of Pool b is greater than Circumference of pool a.
Step-by-step explanation:
Given:
Radius of Pool a = 14 ft
Diameter of pool b = 8.72 m
We need to find which pool has greater circumference.
Solution:
For pool a:
Radius of Pool a = 14 ft
Now we know that;
1 foot = 0.305 m
14 foot = Number of meters in 14 ft.
By Using Unitary method we get;
Number of meters in 14 ft = 4.27 m
Radius of Pool a = 4.27.
Now we know that;
Circumference of Pool is given by 2 times π times radius or π times diameter.
framing in equation form we get;
Circumference of Pool a = [tex]2\pi \times 4.27 =21.8156[/tex]
Rounding to nearest hundredth we get;
Circumference of Pool a = 21.82 m
For Pool b:
diameter of pool b = 8.72 m
Now we know that;
Circumference of Pool is given by 2 times π times radius or π times diameter.
framing in equation form we get;
Circumference of Pool b = [tex]\pi \times 8.72 = 27.3808[/tex]
Rounding to nearest hundredth we get;
Circumference of Pool b = 27.38 m
From above we can say that;
Circumference of Pool b is greater than Circumference of pool a.
Answer:
Pool B has greater circumference.
Step-by-step explanation:
Given:
Pool A has a radius of 14 feet.
Pool B has a diameter of 8.72 meters.
Question asked:
Which pool has a greater circumference ?
Solution:
First of all we will find circumference of each circular pool:-
Pool A
[tex]Circumference\ of\ circle=2\pi r[/tex]
[tex]=2\times\frac{22}{7} \times14\\\\ =\frac{616}{7} =88\ feet[/tex]
Convert it into meter:
1 feet = 0.0305 meter
88 feet = 0.0305 [tex]\times[/tex] 88 = 26.84 meters
Circumference of Pool A = 26.84 meters
Pool B
Diameter = 8.72 meters
[tex]Radius=\frac{diameter}{2}[/tex]
[tex]=\frac{8.72}{2} \\\\ =4.36\ meters[/tex]
[tex]Circumference\ of\ circle=2\pi r[/tex]
[tex]=2\times\frac{22}{7} \times4.36\\ \\ =\frac{191.84}{7} \\ \\ =27.4057\ meters[/tex]
Circumference of Pool B = 27.41 meters
We found that Circumference of Pool A is 26.84 meters while Circumference of Pool B is 27.41 meters.
Conclusion:
Therefore, Pool B has greater circumference.