Answer:
The equation on the the 'point-slope' form of the equation that passes through point (1,9) with the slope -2 will be: [tex]y\:-9=\:-2\left(x\:-\:1\:\right)[/tex]
Step-by-step explanation:
The 'point-slope' form of the equation of a straight line can be written as:
[tex]y\:-y_1\:=\:m\left(x\:-\:x1\:\right)[/tex]
Given
Plugging in the 'point-slope' form of the equation of a straight line
[tex]y\:-y_1\:=\:m\left(x\:-\:x1\:\right)[/tex]
[tex]y\:-9=\:-2\left(x\:-\:1\:\right)[/tex]
Therefore,
The equation on the the 'point-slope' form of the equation that passes through point (1,9) with the slope -2 will be: [tex]y\:-9=\:-2\left(x\:-\:1\:\right)[/tex]