sunj046 sunj046
  • 28-03-2020
  • Mathematics
contestada

What is the minimum possible value for y in the equation y = x^2 + 12x + 5?

Respuesta :

ghanami
ghanami ghanami
  • 30-03-2020

Answer:

Step-by-step explanation:

hello :

y = x² + 12x + 5

y = ( x²+12x+36) -36+5

y= (x+6)²-31.......vertex form when the minimum possible value is : - 31

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