possible solutions for equation [tex]x-12 = \sqrt{x+44}[/tex] is [tex]x=5 , x=20[/tex]
Step-by-step explanation:
Here we have to find the possible solutions to the equation: x-12 = sqrt x+44 .Let's find out:
⇒ [tex]x-12 = \sqrt{x+44}[/tex]
⇒ [tex](x-12)^2 = (\sqrt{x+44})^2[/tex]
⇒ [tex](x^2+144-24x) =x+44[/tex]
⇒ [tex](x^2+144-24x) -(x+44) =0[/tex]
⇒ [tex](x^2+100-25x) =0[/tex]
⇒ [tex]x^2-25x+100 =0[/tex]
⇒ [tex]x^2-20x-5x+100 =0[/tex]
⇒ [tex]x(x-20-5(x-20) =0[/tex]
⇒ [tex](x-5)(x-20)=0[/tex]
⇒ [tex]x-5=0 , x-20=0\\[/tex]
⇒ [tex]x=5 , x=20[/tex]
Therefore , possible solutions for equation [tex]x-12 = \sqrt{x+44}[/tex] is [tex]x=5 , x=20[/tex]