Respuesta :

possible solutions for equation  [tex]x-12 = \sqrt{x+44}[/tex] is  [tex]x=5 , x=20[/tex]

Step-by-step explanation:

Here we have to find  the possible solutions to the equation: x-12 = sqrt x+44 .Let's find out:

⇒ [tex]x-12 = \sqrt{x+44}[/tex]

⇒ [tex](x-12)^2 = (\sqrt{x+44})^2[/tex]

⇒ [tex](x^2+144-24x) =x+44[/tex]

⇒ [tex](x^2+144-24x) -(x+44) =0[/tex]

⇒ [tex](x^2+100-25x) =0[/tex]

⇒ [tex]x^2-25x+100 =0[/tex]

⇒ [tex]x^2-20x-5x+100 =0[/tex]

⇒ [tex]x(x-20-5(x-20) =0[/tex]

⇒ [tex](x-5)(x-20)=0[/tex]

⇒ [tex]x-5=0 , x-20=0\\[/tex]

⇒ [tex]x=5 , x=20[/tex]

Therefore , possible solutions for equation  [tex]x-12 = \sqrt{x+44}[/tex] is  [tex]x=5 , x=20[/tex]

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