Write an equation in slope-intercept form of the line with the parametric equations x = -4t + 3 and y = 5t - 3.
A. y = 5/3x + 4/3
B. y = -5/3x + 4/3
C. y = 5/4x + 3/4
D. y = -5/4x + 3/4

Respuesta :

Answer: D

Step-by-step explanation:

Since both equations have the variable t, rewrite t in terms of x

x = -4t + 3

4t = 3 - x

t = [tex]\frac{3-x}{4}[/tex]

Now you can plug t into y

y = 5t - 3

y = [tex]5*\frac{3-x}{4} -3[/tex]

y = [tex]5*(\frac{3}{4} - \frac{x}{4} ) -3[/tex]

y = [tex]\frac{15}{4} -\frac{5x}{4} -3[/tex]

y = [tex]\frac{15}{4} -\frac{5x}{4} -\frac{12}{4}[/tex]

y = [tex]\frac{-5x}{4} +\frac{3}{4}[/tex]

Answer:

D

Step-by-step explanation:

x = -4t + 3

4t = 3 - x

t = (3 - x)/4

y = 5t - 3

y = 5(3 - x)/4 - 3

y = 15/4 - 5x/4 - 3

y = -5x/4 + 3/4

y = (-5/4)x + 3/4

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