Respuesta :
Answer: [tex]f^{-1}(x) = \frac{x-1}{8}[/tex]
Step-by-step explanation:
Given:
[tex]f(x) = 8x +1[/tex]
First step: Let f(x) be y, the function then becomes
[tex]y = 8x + 1[/tex]
Step 2: Make x the subject of the formula: That is
[tex]8x = y + 1[/tex]
[tex]x = \frac{y-1}{8}[/tex]
Step 3: Replace x with [tex]f^{-1}(x)[/tex] and y with x.
Therefore:
[tex]f^{-1}(x) = \frac{x-1}{8}[/tex]
The inverse of the function f(x)=8x+1 is;
- f-¹(x) = (x - 1)/8
The function can be written as y = 8x + 1 for evaluation.
By making x the subject of the function; we have;
- x = (y - 1)/8
By swapping x and y; we have;
- y = (x - 1)/8
Ultimately, the inverse of the function is; f-¹(x)=8x+1
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