Answer:
I'm pretty sure its 38°
Angle CAB = 111° and angle CDB is equal to angle CAB, therefore, angle CDB = 111°
Angle BCA = 31° and angle DBC is equal to angle BCA, therefore, angle DBC = 31°.
All triangles are comprised of 180°.
180 - (111° + 31°) = 38°
x = 38°
