Answer:
d = 0.377 mm
Explanation:
given data
λ = 633 nm
interference pattern = 3.1 m
spanning a distance = 52 mm
solution
we get here spacing between the slits d that is express as
d = [tex]\frac{m\lambda L}{\Delta y}[/tex] ................1
put here value and we get
and here distance at which the pattern is being observed is much greater than the separation between the maximum of order 10
for bright fringes from m=0 to m=10
d = [tex]\frac{10 \times (633\times 10^{-9})\times 3.1}{(52\times 10^{-3})}[/tex]
d = 0.000377
d = 0.377 mm