The parallax of heavenly body measured from two points diametrically opposite on the equator of the earth is 1.0 min. If the radius is 6400km of the earth , find the distance of the heavenly body from the center of the earth in AV. Take 1AV=1.5×10^2

Respuesta :

Answer:

e = 1 min = 1\60 ×  [tex]\pi/180[/tex]rad

r=1/0

l = 2×6400×[tex]10x^{3}[/tex]×60×180

Explanation:

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