Step-by-step explanation:
Given sequence is: 8, 16, 32, 64, 128
Here, a = 8
[tex]r = \frac{16}{8} = \frac{32}{16} = \frac{64}{32} = \frac{128}{64} = 2 \\ \because \: f(n) = ar^{n - 1} \\ \therefore \: f(n) = 8(2)^{n - 1} \\ where \: n = \{1, \: 2, \: 3, \: 4, \: 5 \}[/tex]
Hence, option B is the correct answer.
