Answer:
The larger trampoline is larger in area by 75.36 feet²
Step-by-step explanation:
There are two trampolines here; the larger and the smaller one.
The trampoline's area can be found using the area of a circle which is πr² or πd²/4, where "r" and "d" represent radius and diameter respectively.
Here we will let D be the diameter of the larger trampoline and d should be taken as the diameter of the smaller trampoline.
So, the difference in area will be πD²/4 - πd²/4 = π/4 (D² - d²), where π is given as 3.14.
So, the area difference = [tex]\frac{3.14}{4}[/tex] × (14² - 10²) = [tex]\frac{3.14}{4}[/tex] × (196 - 100) = [tex]\frac{3.14}{4}[/tex] × (96) = 75.36 feet²
Answer:
The second trampolline is 75.36 feet^2 greater than the first one.
Step-by-step explanation:
Assuming the trampolines are circullar their area will be given by:
A = \pi*(r^2)
The radius of a circle is r = d/2. So for the first trampoline we have:
A_1 = 3.14*[(10/2)^2] = 3.14*(25) = 78.5 feet^2
For the second trampoline we have:
A_2 = 3.14*[(14/2)^2] = 3.14*(49) = 153.86 feet^2
Difference between the areas:
A_2 - A_1 = 153.86 - 78.5 = 75.36 feet^2
From this we can say that the second trampolline is 75.36 feet^2 greater than the first one.
