Answer:
7.5×10^23 molecules of carbon dioxide
Explanation:
H2CO3 → CO2 + H2O
From the balanced reaction equation, one mole of carbonic acid produces one mole of carbon IV oxide.
1.25 moles of carbonic acid will produce 1.25 moles of carbon dioxide
If 1 mole of carbon dioxide contains 6.02×10^23 molecules
1.25 moles of carbon dioxide contains 1.25×6.02×10^23= 7.5×10^23 molecules of carbon dioxide
Answer:
1.25 molecules of CO2 will be produced
Explanation:
Step 1: data given
Number of molecules carbonic acid (H2CO3) = 1.25 molecules
Molar mass carbonic acid (H2CO3) = 62.03 g/mol
Number of Avogadro = 6.022 * 10^23 / moles
Step 2: Calculate moles of H2CO3
Moles H2CO3 = 1.25 molecules / 6.02 *10^23
Moles H2CO3 = 2.076 * 10^-24 moles
Step 3: The equation
H2CO3 → H2O + CO2
For 1 mol H2CO3 we'll have 1 mol H2O and 1 mol CO2
For 2.076 * 10^-24 moles H2CO3 we'll have 2.076 * 10^-24 moles CO2
Step 4: Calculate molecules CO2
Molecules CO2 = moles CO2 * number of Avogadro
Molecules CO2 = 2.076 * 10^-24 moles * 6.02 * 10^23
Molecules CO2 = 1.25 molecules
1.25 molecules of CO2 will be produced
