Question

Please help
In Δ PQR , side Q = 25, m < P= 13* and m < Q = 70*. Find side P to the nearest tenth of an integer.

Answer 1

Answer:

6.0

Step-by-step explanation:

p/sinP = q/sinQ

p/sin(13) = 25/sin(70)

p = sin(13) × 25/sin(70)

p = 5.984697798