Question

A solution of HCl has StartBracket upper H superscript plus EndBracket. = 0.01 M. What is the pH of this solution?
Use p H equals negative logarithm of StartBracket upper H subscript 3 upper O superscript plus EndBracket..
–2
–1
1
2

Answer 1

Answer:

2

Explanation:

Data:

[H⁺] = 0.01 mol·L⁻¹

Calculation:

pH = -log[H₃O⁺] = -log(0.01) = -log(1) - log(10⁻²) = -0 - (-2) = 0 + 2 = 2

Answer 2

Answer:

It is 2

Explanation:

I did it on edg and it said that I got it right

I am sorry if it it wrong

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