Question

oint A is launched horizontally away from a wall and a ( t ) represents Point A's distance from the wall (in meters) in terms of the number of seconds t since the point was launched. Point D is launched from a platform that places it 1 meters from the wall, and Point D travels 1.5 times as fast as Point A.

a. Suppose d(t) represents Point D's distance from the wall (in meters) in terms of the number of seconds t since the points were launched. Write a function formula for d using the function a.

Answer 1

Answer:

$d(t)=1+1.5a(t)$

Step-by-step explanation:

We are given that

Distance traveled by A  in time t seconds from wall =a(t)

Distance of D from wall=1 m

Point D travels 1.5 faster than point A=1.5a(t)

We have to find the function formula for d using the function a.

Let d(t) represents the point's D distance from the wall

To find the function formula we will add distance of D from wall when it launch and the distance traveled by D in time t.

Therefore,

$d(t)=1+1.5a(t)$

This is required function formula for d using the function a.