Answer:
x=0.3
Step-by-step explanation:
we can organize the equation in a convenient form and to simplify
[tex]10^{x+2}=20^{x+1}\\10^{x}*10^{2}=20^{x}*20\\100*10^{x}=20*2^{x}*10^{x}\\100=20*2^{x}\\50=2^{x}[/tex]
now we can apply log in base 2 to get x
[tex]log_{2}(50)=log_{2}(2^{x})\\\\\frac{log(50)}{log(2)}=x\\\\x=0.30[/tex]
where we have used that
[tex]log_{a}(b)=\frac{log(b)}{log(a)}[/tex]
I hope this is useful for you
regards