Answer:
x = -[tex]\frac{5}{4}[/tex] + [tex]\frac{\sqrt{47} }{2}[/tex] i or -[tex]\frac{5}{4}[/tex] - [tex]\frac{\sqrt{47} }{2}[/tex] i
x = -1.25 + 3.43 i or - 1.25 - 3.43 i
Step-by-step explanation:
solve 2x² + 5x + 9 = 0 using quadratic formula
The quadratic formula is;
x = -b ±√b² - 4ac / 2a
a = 2 b = 5 and c= 9
We can now proceed to insert the values into the formula;
x = -5 ± √5² - 4(2)(9) / 2(2)
x = -5±√25 -72 / 4
x = -5 ± √-47 / 4
x = -[tex]\frac{5}{4}[/tex] ±[tex]\sqrt{\frac{47}{4} }[/tex] . [tex]\sqrt{-1}[/tex]
But [tex]\sqrt{-1}[/tex] = i
x = -[tex]\frac{5}{4}[/tex] ±[tex]\sqrt{\frac{47}{4} }[/tex] . i
=-[tex]\frac{5}{4}[/tex] ± [tex]\frac{\sqrt{47} }{2}[/tex] i
x = -[tex]\frac{5}{4}[/tex] + [tex]\frac{\sqrt{47} }{2}[/tex] i or -[tex]\frac{5}{4}[/tex] - [tex]\frac{\sqrt{47} }{2}[/tex] i
x = -1.25 + 3.43 i or - 1.25 - 3.43 i