Answer:
Step-by-step explanation:
The diagonal of a square is the same thing as the hypotenuse of a right triangle. This right triangle is a 45-45-90 since the sides are made up of sides of a square which all measure the same length, x.
Using Pythagorean's Theorem,
[tex]x^2+x^2=3^2[/tex] and
[tex]2x^2=9[/tex] and
[tex]x^2=\frac{9}{2}[/tex] and taking the square root of both sides gives us that
[tex]x=\frac{\sqrt{9} }{\sqrt{2} }[/tex] which simplifies to
[tex]x=\frac{3}{\sqrt{2} }[/tex] I'm assuming that your teacher has told you about rationalizing the denominator when you've got a radical there, so we will do that by multiplying by [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] :
[tex]x=\frac{3}{\sqrt{2} }*\frac{\sqrt{2} }{\sqrt{2} }[/tex] which gives us
[tex]x=\frac{3\sqrt{2} }{2}[/tex]