Question

Force A has a magnitude F and acts for the time Δt, force B has a magnitude 2F and acts for the time Δt/3, force C has a magnitude 5F and acts for the time Δt/10, and force D has a magnitude 10F and acts for the time Δt/100. Rank these forces in order of decreasing impulse.

Answer 1

Answer:

$A>B>C>D$

Explanation:

calculate impulse in each case:

As impulse is the product of force and time.

• Force A:

$I_A=F.\Delta t$

• Force B:

$I_B=2F.\frac{\Delta t}{3}=\frac{2}{3} \times F.\Delta t$

• Force C:

$I_C=5F\times \frac{\Delta t}{10} =\frac{1}{2} \times F.\Delta t$

• Force D:

$I_D=10F\times \frac{\Delta t}{100} =\frac{1}{10} F.\Delta t$

Now the force can be ranked as:

$A>B>C>D$