Answer:
C. The domain is [-k, ∞), and the range is [c, ∞).
Step-by-step explanation:
f(x) = a(x + k)^(1/n) + c
1/n means the nth root. Based on the graph, n is even, so x + k must be non-negative.
x + k ≥ 0
x ≥ -k
When x = -k:
f(-k) = a(-k + k)^(1/n) + c
f(-k) = c
So the domain is [-k, ∞), and the range is [c, ∞).
