Question

Use AGHJ, where A , B , and C are midpoints of the sides.
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When GH = 72 – 1 and CB = 4z - 3 , what is GA ?

Answer 1

Answer:

GA= 3z+-4

Step-by-step explanation:

(7z - 1) - (4z - 3)

3z+-4

Answer 2

Using the midpoint principle, the point GA is the midpoint of the line segment GH ; Hence, the point GA can be represented as $\frac{7z - 1}{2}$

Since A is the midpoint of the line GH ; Hence, GH = GA + AH

• GA = AH

• GH = 2(GA)

GA = $\frac{GH}{2}$

$GA = \frac{7z - 1}{2}$

Therefore, GA would be $\frac{7z - 1}{2}$

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